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48x^2-19.6x+1.47=0
a = 48; b = -19.6; c = +1.47;
Δ = b2-4ac
Δ = -19.62-4·48·1.47
Δ = 101.92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19.6)-\sqrt{101.92}}{2*48}=\frac{19.6-\sqrt{101.92}}{96} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19.6)+\sqrt{101.92}}{2*48}=\frac{19.6+\sqrt{101.92}}{96} $
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